(x^2-4)(x^2-12x+36)=0

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Solution for (x^2-4)(x^2-12x+36)=0 equation: 


Simplifying
(x2 + -4)(x2 + -12x + 36) = 0

Reorder the terms:
(-4 + x2)(x2 + -12x + 36) = 0

Reorder the terms:
(-4 + x2)(36 + -12x + x2) = 0

Multiply (-4 + x2) * (36 + -12x + x2)
(-4(36 + -12x + x2) + x2(36 + -12x + x2)) = 0
((36 * -4 + -12x * -4 + x2 * -4) + x2(36 + -12x + x2)) = 0
((-144 + 48x + -4x2) + x2(36 + -12x + x2)) = 0
(-144 + 48x + -4x2 + (36 * x2 + -12x * x2 + x2 * x2)) = 0
(-144 + 48x + -4x2 + (36x2 + -12x3 + x4)) = 0

Combine like terms: -4x2 + 36x2 = 32x2
(-144 + 48x + 32x2 + -12x3 + x4) = 0

Solving
-144 + 48x + 32x2 + -12x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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